How do i call a function inside another function?

i wrote 2 functions separately. in one of these functions, i need to call the other function inside it? how do i do that? Thanks :)

Respuestas (2)

KSSV
KSSV el 3 de Sept. de 2016
I am giving an example here. The below first function calls a seconds function to calculate the sum of three numbers.
function K = firstfunction(a,b,c)
L = secondfunction(b,c) ;
K = a+L ;
This is the second function which calculates sum of two numbers.
function L = secondfunction(b,c)
L = b+c ;
Call the first function in Main file/ matlab work space:
s = firstfunction(1,2,3) ;

3 comentarios

My question is will the variable L be local or global to the calling function?
Stephen23
Stephen23 el 18 de Dic. de 2018
Editada: Stephen23 el 18 de Dic. de 2018
"My question is will the variable L be local or global to the calling function?"
L is not declared as global. It exists
  1. in the workspace where it is defined, and
  2. where it is passed as an output argument.
What do you mean by "the calling function" ?
@Soumen Kuma Mondal: Try it. It is very cheap to run the shown code and to use the debugger to step throught the code line by line. Then you can see in the WorkspaceBrowser, which variables are existing.
You need the command global to make a variable global. Another method to share data is to created a nested function:
function K = firstfunction(a,b,c)
L = secondfunction(b,c) ;
K = a+L ;
function L = secondfunction(b,c)
L = b+c ;
disp(K)
end
end
Now secondFunction is visible inside the firstFunction only and e.g. K is existing inside secondFunction.

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KSSV
KSSV el 3 de Sept. de 2016

0 votos

simple....write the function (output = functionname(inputs)) inside the function you want...

1 comentario

Mohammed
Mohammed el 3 de Sept. de 2016
Thank you! i tried that but it does not work:( so i wrote the main function and then i called the other function inside it(in the same format you have specified). i think this is because the inputs of the function i called are not specified so MATLAB will not be able to run the code while it contains other unknowns from the previous function so i think i would have to enter the inputs of the other function i called but i do not know how to do that!

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el 3 de Sept. de 2016

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Jan
el 18 de Dic. de 2018

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