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what is my problem in using datevec?

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Ryoung seob Kwon
Ryoung seob Kwon el 18 de Sept. de 2016
Editada: Stephen23 el 21 de Sept. de 2016
cd('C:\Users\Kwom\Desktop');
% I loaded my folder
file=xlsread('Week02_climate_data_analysis.xls');
% I loaded my Excel file in my folder. - 14244x5 double
% in the excel file, the column is date (ex. 19730101) the row is temperature, humidity...etc.
% my purpose is to separate the spring(March~May), summer(June~August), fall(September~November), winter(December~February) by using 'datevec' in Excel's column.
% So, I made these ones...
date=num2str(file(:,1));
dateformat='yyyy,mm,dd';
datevec(date,dateformat)
However, it has a error... I don't know what is a problem...
What should I do...?
  1 comentario
Stephen23
Stephen23 el 21 de Sept. de 2016
Editada: Stephen23 el 21 de Sept. de 2016
"What should I do...?"
Use the correct date format string:
>> datevec('19730101','yyyymmdd')
ans =
1973 1 1 0 0 0

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Respuestas (1)

Saurabh Gupta
Saurabh Gupta el 21 de Sept. de 2016
Hello Ryoung,
Based on your description, it seems that your date values are in the format 'yyyymmdd' (ex. 19730101), but you are using the date format as ‘yyyy,mm,dd’ for the datevec function. Your ‘dateformat’ string should match the date format in your ‘date’ string (i.e. the format of the date values in your source file).

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