Problems with legend using imagesc

8 visualizaciones (últimos 30 días)
Robert
Robert el 4 de Oct. de 2016
Comentada: Robert el 4 de Oct. de 2016
I have the following code, I have adapted it from another code and I think that is where I am getting stuck.
basically I have a 35x43 matrix of numbers 1-6 and NaNs. I want to plot is as a map using imagesc with different colours for each number (1,2,3,4,5,6). I have attached the data, and my code is below.
Thanks in advance for any help
figure(6)
subplot(1,2,1)
imagesc(lut)
title('Distribution of Different Land Use Types in Australia')
ylabel('Longitude')
xlabel('Latitude')
caxis([0, 6])
myColorMap = jet(6);
myColorMap(1,:) = 1;
colormap(myColorMap);
M = jet(6);
hold on
L = line(ones(6),ones(6));
set(L,{'color'},mat2cell(M,ones(1,6),3))
[legh,objh,outh,outm] = legend('First','Second','Location','Southeast');
set(objh,'linewidth',200);
legend(1,'Forest',2,'Shrubland',3,'Savanna',4,'Grassland',5,'Agricultural',6,'Barron');
grid on
ax = gca
ax.GridAlpha = .2
ax.XTick = [5 10 15 20 25 30 35 40];
ax.YTick = [5 10 15 20 25 30];
ax.XTickLabel = {'118^{o}E','123^{o}E','128^{o}E', '133^{o}E', '138^{o}E', '143^{o}E','148^{o}E', '153^{o}E'};
ax.YTickLabel = {'13^{o}S','18^{o}S','23^{o}S','28^{o}S','33^{o}S','38^{o}S'};
ax.TickLength =[0.0 0.0]

Respuestas (1)

KSSV
KSSV el 4 de Oct. de 2016
Replace
legend(1,'Forest',2,'Shrubland',3,'Savanna',4,'Grassland',5,'Agricultural',6,'Barron');
with
legend('Forest' ,'Shrubland', 'Savanna','Grassland' , 'Agricultural' ,'Barron');
  6 comentarios
KSSV
KSSV el 4 de Oct. de 2016
Try
image(lut)
instead
imagesc(lut)
Robert
Robert el 4 de Oct. de 2016
This does not fix the problem either.
I am pretty sure the answer lies within these lines
caxis([0, 6])
myColorMap = jet(6);
myColorMap(1,:) = 1;
colormap(myColorMap);
M = jet(6);
hold on
L = line(ones(6),ones(6));
set(L,{'color'},mat2cell(M,ones(1,6),3))
I have tried various combinations of numbers but with no luck...

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