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Curve fitting: What does LAR do?

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able_archer
able_archer el 1 de Dic. de 2016
Comentada: able_archer el 1 de Dic. de 2016
Hello, when conducting a nonlinear least squares regression, one can select 'LAR' (=least absolute residuals) under 'fitoptions'. This is a bit confusing because afaik LAR by definition does NOT minimize squared, but linear residuals. So if 'LAR' is selected, the regression is actually not based on nonlinear least squares, right?
Greetings Vince
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Tamir Suliman
Tamir Suliman el 1 de Dic. de 2016
I think this has been answered in
https://www.mathworks.com/matlabcentral/answers/81143-fit-and-polyfit-lar-vs-least-squares

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John D'Errico
John D'Errico el 1 de Dic. de 2016
Editada: John D'Errico el 1 de Dic. de 2016
I don't understand what is confusing. The sum of the absolute values of the residuals is clearly NOT least squares, thus a minimum sum of squares of residuals. If it was, there would be no point in offering it as an alternative.
Least squares puts more importance on the large residuals. For example, suppose you have two cases, based on two sets of parameters. We need consider only two points.
Case 1: Resid1 = 1, Resid2 = 1
case 2: Resid1 = 0, Resid2 = 2
For a least squares solver, the two cases are very different. Case 1 would be preferred, since the sum of squares is 2, versus 4 for the latter. So whatever set of parameters generated case 1 will be chosen as better.
In a LAR scheme (also called MAD, for minimum absolute deviations) the sum of the absolute residuals are identical. Neither solution would be preferred over the other.
One reason one might use such a scheme is it will be less sensitive to outliers in the data, whereas least squares tends to be jerked around by outliers quite easily.
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able_archer
able_archer el 1 de Dic. de 2016
Thanks for your answer.
So LAR does indeed not use Least Squares. What confused me about it is that although you set 'Robust' to 'LAR', you still have 'NonlinearLeastSquares' as 'Method' (see below) which could make one think 'LAR' was a nonlinear least squares method though this is not the case.
Normalize: 'off'
Exclude: []
Weights: []
Method: 'NonlinearLeastSquares'
Robust: 'LAR'
StartPoint: [0.1200 0.8500 75 0]
Lower: [-Inf -Inf -Inf -Inf]
Upper: [Inf Inf Inf Inf]
Algorithm: 'Trust-Region'
DiffMinChange: 1.0000e-08
DiffMaxChange: 0.1000
Display: 'Notify'
MaxFunEvals: 10000
MaxIter: 10000
TolFun: 1.0000e-12
TolX: 1.0000e-12

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