Error using min Matrix dimensions must agree.

Greetings ... I will be new in matlab and in this community, I am going to you because I have a small problem with a project, which tries to make a fuzzy controller ... I got a code from a controller that made a few Changes insignificant, but it is not working, and shows me an error in the use of the min () function. Someone who can help me with this problem please
%
paso = 0.01;
valCong=0:paso:1;
PC=trapmf(valCong,[0 0 0.1 0.35]);
MC=trimf(valCong,[0.2 0.5 0.8]);
AC=trapmf(valCong,[0.65 0.9 1 1]);
paso2=0.1;
tiempo=0:paso2:55;
PTV=trapmf(tiempo,[0 0 7.5 15]);
MTV=trimf(tiempo,[10 27.5 45]);
LTV=trapmf(tiempo,[40 47.5 55 55]);
nivCong=0.5;
n=find(valCong==nivCong);
B1 = min(PTV,PC(n));
B2 = min(MTV,MC(n));
B3 = min(LTV,AC(n));
B = max(B1,max(B2,B3));
TV = defuzz(tiempo,B,'centroid');
tiempoVerde=round(TV,0);
Este codigo me da el siguiente error
"Error using min
Matrix dimensions must agree.
Error in Oquendo_Calama (line 53)
B1 = min(PTV,PC(n));"

Respuestas (2)

John D'Errico
John D'Errico el 11 de En. de 2017
Editada: John D'Errico el 11 de En. de 2017

0 votos

Apparently, PTV is a matrix. Right? What size is that matrix?
Apparently, PC(n) is a matrix. Right? What size is that matrix?
They are not the same size. Read the error message. What sense would it make to try to take the min between a 3x3 and a 2x2 matrix? None. While I don't know the actual sizes of your matrices, the above statement still applies.

1 comentario

Stephen23
Stephen23 el 11 de En. de 2017
Cesar Herbas's "Answer" moved here:
What happens is that I try to do is to program my own fuzzy controller, and that's why I'm not using Fuzzy Logic Toolbox, so far as PTV and PC are not actually arrays but rather they are fuzzy sets, and I explained that "B1 = Min (PTV, PC (n)) "makes a cut of the PTV set at the height of the fusing value 'n' and that value stores it in B1

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Walter Roberson
Walter Roberson el 11 de En. de 2017
Your find() operation is returning the empty matrix for n.
You have find(valCong==nivCong) which attempts to check for bit-for-bit equality between the floating point number nivCong in the vector 0:paso:1 where paso is not an integer (paso = 0.01). Due to accumulated floating point roundoff, there might not be any entry that exactly equals 0.5.
You should consider using
[tf, n] = ismembertol(nivCong, valCong);
and you should check to be sure that tf returns true (if it is false, no entries matched to within tolerance.)

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