How do you rewrite the nested if statement as a loop?

 clear; close all

 n = 4000;

 % (A) Use rand to generate randomly distributed points:
 Rand_Number = rand(n, 2);
 x = Rand_Number(:,1)*2-1;
 y = Rand_Number(:,2)*2-1;

 hold on
 figure(1)
 subplot(3,1,1)
 plot(x,y,'r.')
 title('Random Points Generated Using "rand"')
 xlabel('x')
 ylabel('y') 

 subplot(3,1,2)
 count = zeros(1,20);
 for i=1:length(x)
     if x(i) >= -1 && x(i) <= -0.9
         count(1) = count(1)+1;
     elseif x(i) >-0.9 && x(i)<-0.8
         count(2) = count(2)+1;
     elseif x(i)>-0.8 && x(i)<-0.7
         count(3) = count(3)+1;
     elseif x(i)>-0.7 && x(i)<-0.6
         count(4) = count(4)+1;
     elseif x(i)>-0.6 && x(i)<-0.5
         count(5) = count(5)+1;
     elseif x(i)>-0.5 && x(i)<-0.4
         count(6) = count(6)+1;
     elseif x(i)>-0.4 && x(i)<-0.3
         count(7) = count(7)+1;
     elseif x(i)>-0.3 && x(i)<-0.2
         count(8) = count(8)+1;
     elseif x(i)>-0.2 && x(i)<-0.1
         count(9) = count(9)+1;
     elseif x(i)>-0.1 && x(i)<0
         count(10) = count(10)+1;
     elseif x(i)>0 && x(i)<0.1
         count(11) = count(11)+1;
     elseif x(i)>0.1 && x(i)<0.2
         count(12) = count(12)+1;
     elseif x(i)>0.2 && x(i)<0.3
         count(13) = count(13)+1;
     elseif x(i)>0.3 && x(i)<0.4
         count(14) = count(14)+1;
     elseif x(i)>0.4 && x(i)<0.5
         count(15) = count(15)+1;
     elseif x(i)>0.5 && x(i)<0.6
         count(16) = count(16)+1;
     elseif x(i)>0.6 && x(i)<0.7
         count(17) = count(17)+1;
     elseif x(i)>0.7 && x(i)<0.8
         count(18) = count(18)+1;
     elseif x(i)>0.8 && x(i)<0.9
         count(19) = count(19)+1;
     elseif x(i)>0.9 && x(i)<=1
         count(20) = count(20)+1;
     end
 end
 X=-.95:.1:1;
 bar(X,count)
 title('Distribution of Points')
 xlabel('x')
 ylabel('y')

 subplot(3,1,3)
 hist(x)
 title('Histogram of Points')
 xlabel('x')
 ylabel('y')

 hold off
 end

Answer 1

[Jan]

Are you really sure, that you want to exclude e.g. the value -0.8 from your results?

Do you really want a for loop, although a single call to histcounts might solve this efficiently?

count = histcounts(x, -1:0.1:1)