how to get the same elements from many different vectors and each index for each vectors?

for example, now I have three vectors as below:

v1=['a','b','c','d','e','f']; v2=['a','c','d','f','g']; v3=['c','d','e','j'];

Now I want to get the same elements ['c','d'] and index1=[3,4],index2=[2,3],index3=[1,2];

Is there some good function for this?

Answer 1

[KSSV]

doc intersect

clc; clear all ;
v1=[{'a'},{'b'},{'c'},{'d'},{'e'},{'f'}]; 
v2=[{'a'},{'c'},{'d'},{'f'},{'g'}]; 
v3=[{'c'},{'d'},{'e'},{'j'}];
[a1,b1,c1] = intersect(v1,v2) ;
[a2,idx2,idx3] = intersect(a1,v3) ;
[common,idx1,c3] = intersect(v1,a2) ;
common
idx1
idx2
idx3

[vx2008]

thanks for your reply;

yes it works well; but what if there are many vectors? such as 100 vectors.

[KSSV]

Have a look on this file: https://in.mathworks.com/matlabcentral/fileexchange/6144-mintersect-multiple-set-intersection

[Stephen23]

@KSSV: why make this so complicated?:

 v1=[{'a'},{'b'},{'c'},{'d'},{'e'},{'f'}];

why not simply write the cell array itself:

 v1 = {'a','b','c','d','e','f'};

which is simpler to read and will make your code faster too.

[KSSV]

@Stephen yes you are right....thank you for the comment.