Matrix with binomial permutation

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Zheng Liu
Zheng Liu el 13 de Feb. de 2017
Comentada: Zheng Liu el 13 de Feb. de 2017
I really had trouble finding the right words for the question. I'll try my best. Given a numerical number k (k>1), I want to get a [2^k, k] matrix with all possible binomial permutation. for K = 2, I hope to get: [1 1; 1 2; 2 1; 2 2]. for k = 3, the matrix will look like: [1 1 1; 1 1 2; 1 2 1; 1 2 2; 2 1 1; 2 1 2; 2 2 1; 2 2 2]. I could do for loop for each condition, like for k=3:
mat = [];
for digit1 = 1:2
for digit2 = 1:2
for digit3 = 1:2
mat(size(mat,1)+1,:) = [digit1 digit2 digit3];
end
end
end
But this is not generalized and efficient. Is there any thoughts on generating such matrix? Thanks!

Respuesta aceptada

Honglei Chen
Honglei Chen el 13 de Feb. de 2017
dec2bin(0:2^K-1)-'0'+1
HTH
  1 comentario
Zheng Liu
Zheng Liu el 13 de Feb. de 2017
That's why we like binary. Thanks!

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