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Calculating a mean matrix from a large number of matrices

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Aaron Smith
Aaron Smith el 13 de Mzo. de 2017
Comentada: Aaron Smith el 15 de Mzo. de 2017
I have been trying to calculate an average matrix from 50 matrices. Using squeeze and cat, i have calculated the mean to two matrices. My question was; how is it possible to get the mean of 50 matrices. I have a code to open the files from a folder and reformat and bin them.
myFolder = uigetdir('C:\Users\c13459232\Documents\MATLAB');
if ~isdir(myFolder)
errorMessage = sprintf('Error: the following folder does not exist: \n%s', myFolder);
uiwait(warndlg(errorMessage));
return;
end
outFolder = fullfile(myFolder, 'output');
mkdir(outFolder);
filePattern = fullfile(myFolder, '*.asc');
Files = dir(filePattern);
for k = 1 : length(Files)
baseFileName = Files(k).name;
FileName = fullfile(myFolder, baseFileName);
fprintf(1, 'Now reading %s\n', FileName);
fid = fopen(FileName);
Cell = textscan( fid, '%d', 'delimiter', ';')
fclose(fid);
Data = cell2mat(Cell);
N = 1024;
skip = 2;
Finish0 = reshape(Data, N, [])';
Finish1 = Finish0(1:skip:end, 1:skip:end);
newFileName = fullfile(outFolder, ['finish_' sprintf('%03d', k) '.txt']);
dlmwrite(newFileName, Finish0, ';');
eval(['finish_' sprintf('%03d', k) ' = Finish1;']);
disp([':: Now writing ' newFileName]);
end
Where could i insert squeeze(cat()) to average all of these matrices. The example I found to get the mean of two matrices is:
c2 = squeeze(mean(cat(3,finish_002,finish_004), 3));
Would you suggest a variation on this code or is there a better way to get an average matrix?
  9 comentarios
Stephen23
Stephen23 el 14 de Mzo. de 2017
@Aaron Smith: using indexing is going to be much easier to work with.
If you want to know why, read that link I gave you.
Guillaume
Guillaume el 14 de Mzo. de 2017
Editada: Guillaume el 14 de Mzo. de 2017
"You see, when each full matrix is saved as a single cell in a cell array, I'm not sure if this will give me the freedom i need to plot each one individually and to bin each one individually"
It's the exact opposite. Having all the matrices as cells of a cell array gives you the freedom to treat each them individually any way you want. Use a fixed index in your cell array, and the freedom to operate on all them at once. Having individually named matrices you sacrifice the latter and don't gain anything in return.
As a rule, if you're numbering variables you're doing something wrong. These numbered variables are obviously related so they should be stored together in a container of some sort (matrix, cell array, containers.map, whatever).
This would make your question dead easy to solve:
%finish: cell array of matrices
meanofallmatrices = mean(cat(3, finish{:}), 3); %no need for squeeze
And since all the matrices are obviously the same size, you could store them directly as a 3D array instead of cell array (with again no loss of freedom)
Stephen is right, eval is completely the wrong approach. Here be dragons!

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Respuestas (1)

Thorsten
Thorsten el 13 de Mzo. de 2017
Editada: Thorsten el 14 de Mzo. de 2017
In the for-loop, you can just use
if k == 1,
M = 1/length(Files)*Data;
else
M = M + 1/length(Files)*Data;
end
Then after the loop, M is the mean of the matrices.
  10 comentarios
Guillaume
Guillaume el 15 de Mzo. de 2017
Editada: Guillaume el 15 de Mzo. de 2017
You've got a closing bracket in the wrong location, the second 3 is an argument to mean, not cat.
mean(cat(3, finishCell{:}), 3);
%bracket goes here ------^
That second 3 tells mean to average across pages instead of the default across rows as you saw.
Aaron Smith
Aaron Smith el 15 de Mzo. de 2017
Ah, I see.
Thanks a million Guillaume

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