Why this program for automatical segmentation doesn´t work?
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Dear all,
I have this code for automatical segmentation, but I don´t have output, MATLAB is only "busy".
function [mu,mask]=kmeans(ima,k)
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
%
% kmeans image segmentation
%
% Input:
% ima: grey color image
% k: Number of classes
% Output:
% mu: vector of class means
% mask: clasification image mask
%
% Author: Jose Vicente Manjon Herrera
% Email: jmanjon@fis.upv.es
% Date: 27-08-2005
%
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
% check image
k=3;
ima = 'thorax-mdl.jpg';
ima=double(ima);
copy=ima; % make a copy
ima=ima(:); % vectorize ima
mi=min(ima); % deal with negative
ima=ima-mi+1; % and zero values
s=length(ima);
% create image histogram
ima=round(ima);
m=max(ima)+1;
h=zeros(1,m);
hc=zeros(1,m);
for i=1:s
if(ima(i)>0) h(ima(i))=h(ima(i))+1;end;
end
ind=find(h);
hl=length(ind);
% initiate centroids
% k=str2double(k);
mu=(1:k)*m/(k+1);
% start process
while(true)
oldmu=mu;
% current classification
for i=1:hl
c=abs(ind(i)-mu);
cc=find(c==min(c));
hc(ind(i))=cc(1);
end
%recalculation of means
for i=1:k,
a=find(hc==i);
mu(i)=sum(a.*h(a))/sum(h(a));
end
if(mu==oldmu) break;end;
end
% calculate mask
s=size(copy);
mask=zeros(s);
for i=1:s(1),
for j=1:s(2),
c=abs(copy(i,j)-mu);
a=find(c==min(c));
mask(i,j)=a(1);
end
end
mu=mu+mi-1;
imshow(mask,[])% recover real range
I don´t know, why I don´t have any output.I attach original image. Can you advise me?
Thank you for your answers.
0 comentarios
Respuestas (1)
Jan
el 27 de Mzo. de 2017
Editada: Jan
el 27 de Mzo. de 2017
Then obviously the condition if mu==oldmu is never true. This can happen even in the case of convergence if the result oscillate e.g. in the last sigfnificant digit.
You can monitor this easily:
count = 0;
while (true)
...
count = count + 1;
if count > 1000
sprintf('%d iterations reached: mu = %.16g, oldmu = %.16g\n', count, mu, oldmu);
end
if (mu==oldmu) break; end
end
Most likely a tolerance helps:
if abs(mu - oldmu) < 1e-6
break;
end
5 comentarios
Jan
el 29 de Mzo. de 2017
Sorry, Veronika, I'm telling you the third time now, that "mu==oldmu" cannot be expected to happen. The limited precision can lead to oscillating rounding effects even if te algorithm has converged. Inserting this command twice does not help also.
Please insert a tolerance:
if abs(mu - oldmu) < 1e-6 % Or whatever you accept as converged
break;
end
Ver también
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