i have a important question!! ( function "randfixedsum" )

i successd in create matrix 'x' from "randfixedsum"

http://www.mathworks.com/matlabcentral/fileexchange/9700-random-vectors-with-fixed-sum/content/randfixedsum.m

in here, 'x' is formed 'double'. and 'x' can recreate as integer by using "round", "ceil", or "floor"

by the way,

how to create 'x' by way for 'integer' by itself?

Answer 1

[Roger Stafford]

I think you might prefer to use the following code rather than using randfixedsum and rounding to integers:

   function R = randfixedsumint(m,n,S);
   % This generates an m by n array R.  Each row will sum to S, and
   % all elements are all non-negative integers.  The probabilities
   % of each possible set of row elements are all equal.
   % RAS - Mar. 4, 2017
   if ceil(m)~=m|ceil(n)~=n|ceil(S)~=S|m<1|n<1|S<0
    error('Improper arguments')
   else
    P = ones(S+1,n);
    for in = n-1:-1:1
     P(:,in) = cumsum(P(:,in+1));
    end
    R = zeros(m,n);
    for im = 1:m
     s = S;
     for in = 1:n
      R(im,in) = sum(P(s+1,in)*rand<=P(1:s,in));
      s = s-R(im,in);
     end
    end
   end
   return

Answer 2

[KSSV]

doc uint8

[Brian Kim]

where apply that?

[KSSV]

uint8 covers double to int.

x_int = uint8(x) ;