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Write a function called sindeg that takes a matrix input called deg. The function returns a matrix of the same size as deg with elements containing the sine of the corresponding element of deg and mean of the sine.we are nor allowed builtin functions

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function [sine,mean_sine] = sindeg(deg)
sine = (exp(i*deg) - exp(-i*deg))/(2i)
mean_sine=sine/length(deg)
I am not getting right value. instead I am getting this. sine = 0.1060 -0.2624 0.5514 0.6702 0.5514 0.9866 -0.9483 mean_sine = 0.0151 -0.0375 0.0788 0.0957 0.0788 0.1409 -0.1355 ans = 0.1060 -0.2624 0.5514 0.6702 0.5514 0.9866 -0.9483

Respuestas (2)

Jan
Jan el 17 de Mayo de 2017
Editada: Jan el 17 de Mayo de 2017
mean_sine = sum(sine) / length(deg);
% ^^^
The mean is the sum of the elements divided by the number of elements.
we are nor allowed builtin functions
This is nonsense. I know that teachers ask such questions, but:
a = b
calls the builtin function subsassgn already.
"deg" sounds like the input is in degrees. Then convert the values to radians at first.
Append semicolons to the lines to suppress the output and call your function like
[sine,mean_sine] = sindeg(deg)

Isaac DeVaughn
Isaac DeVaughn el 4 de En. de 2018
I think what they were talking about with this question is that you can't use sind the function that allows for inputs of degrees which easily solves the question. I'm slightly confused by the 2nd line of you code because you don't actually take the sin of anything.
  2 comentarios
John D'Errico
John D'Errico el 4 de En. de 2018
Editada: John D'Errico el 4 de En. de 2018
Please don't answer a question if you only have a comment. Hint: There are comments when you want to comment.
Jan
Jan el 4 de En. de 2018
Editada: Jan el 4 de En. de 2018
@Isaac: Compare:
deg = 123.4;
rad = deg * pi / 180;
sin1 = (exp(1i*rad) - exp(-1i*rad)) / (2i)
sin2 = sin(rad)
exp(1i * x) = cos(x) + 1i * sin(x)

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