Dipole antenna far-field pattern
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Vinci
el 22 de Mayo de 2017
Respondida: Omkar Savkur
el 29 de Jun. de 2021
I need to plot the radiation pattern for a dipole antenna of length L=lambda/2. The example plot given was of L=1.4*lambda.
Example plot of L=1.4*lambda:
My code to try and reproduce the plot for L=1.4*lambda:
%Wavelength
lam = 1;
%Dipole antanna
L = 1.4*lam;
%Phase constant
B = 2*pi/lam;
t = 0:0.01:2*pi;
% Far-field pattern equation
E = abs((cos(B*L/2*cos(t))-cos(B*L/2))./sin(t));
figure()
polar(t,E)
Plot from this code:
I can't figure out where I'm going wrong with this one...
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Respuesta aceptada
David Goodmanson
el 22 de Mayo de 2017
Hi Vinci, power is proportional to the square of the electric field, so if you use
E2 = abs((cos(B*L/2*cos(t))-cos(B*L/2))./sin(t)).^2;
figure()
polar(t,E2)
the correct figure should pop up.
Más respuestas (1)
Omkar Savkur
el 29 de Jun. de 2021
Hi Vinci, building off David's answer, you can use the polarpattern function to help plot the radiation power. You can interact with the plot and specify the plot parameters all in one line.
% Wavelength
lam = 1;
% Dipole antanna
L = 1.4*lam;
% Phase constant
B = 2*pi/lam;
% Angle in degrees
t = 0:0.1:360;
% Far-field pattern equation
E = abs((cos(B*L/2*cosd(t))-cos(B*L/2))./sind(t)).^2;
figure(1)
polarpattern(t,E,'AngleResolution',30)
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