Extract data based on columns

Altruists,
I have the data in the following matrix.
Year month value
2000 1 10
2000 2 20
2000 3 30
I have to extract this values to the following matrix in repetition, for example:
Year month value
2000 1 ?
2000 1 ?
2000 2 ?
Thanks

Respuestas (2)

Walter Roberson
Walter Roberson el 5 de Jun. de 2017
Editada: Walter Roberson el 5 de Jun. de 2017

0 votos

YourMatrix = [2000 1 10
2000 2 20
2000 3 30];
probe_rows = [2000 1
2000 1
2000 2];
[uniqYM, ~, uniq_rowidx] = unique(YourMatrix(:,1:2), 'rows', 'stable');
[tf, index_in_uniqYM] = ismember(probe_rows, uniqYM, 'rows');
valid_idx_in_uniqYM = index_in_uniqYM(tf);
output = YourMatrix( ismember(uniq_rowidx, valid_idx_in_uniqYM), :);
Note: this code was specifically designed with the possibility that the year and month entries in the original matrix might not be unique, that you might need to retrieve multiple rows.

2 comentarios

novice modeler
novice modeler el 5 de Jun. de 2017
Thanks for the reply. Actually, the original matrix contains no repetitive entries but the matrix in problem requires to retrieve repetitive entries. Would you please let me know your answer for this.
YourMatrix = [2000 1 10
2000 2 20
2000 3 30];
probe_rows = [2000 1
2000 1
2000 2];
[tf, index_in_original] = ismember(probe_rows, YourMatrix(:, [1 2]), 'rows');
output = YourMatrix( index_in_original(tf), : );

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Guillaume
Guillaume el 5 de Jun. de 2017

0 votos

If your matrices are actually tables as your formatting sort of imply, then it's trivially done with join or outerjoin (depending on whether or not you want to include rows that don't match:
%inputs as table:
data = table([2000; 2000; 2000], [1; 2; 3], [10; 20; 30], 'VariableNames', {'year', 'month', 'value'})
probe = table([2000; 2000; 2000], [1; 1; 2], 'VariableNames', {'year', 'month'});
%include only rows that match
result = join(probe, data)
%include rows of probe that do not match
result = outerjoin(probe, data, 'Type', 'left');
If your inputs are actually matrices, then convert them to tables or use Walter's answer.

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Preguntada:

el 4 de Jun. de 2017

Respondida:

el 5 de Jun. de 2017

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