recurrence relation for any given 'n'.
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Venkata
el 20 de Jun. de 2017
Comentada: Venkata
el 7 de Jul. de 2017
How to compute A_j^(2n) for any 'n' using A_j^(2).
Here, n=2,3,4,...; and j=1:n-1.
Any kind of help is highly appreciated.
Thank you.
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Walter Roberson
el 21 de Jun. de 2017
If you have the Symbolic toolbox, you could use evalin(symengine) or feval(symengine) to call into MuPAD in order to take advantage of solve() of a rec() recurrence structure
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Walter Roberson
el 6 de Jul. de 2017
I tossed together the attached. I did not test it with functions that return multiple outputs.
Aj_2n_better and Aj_2 are the same as last time. memoizefun is new (I just wrote it) and A_driver_cache is almost the same as the previous A_driver_better except for calling memoizefun instead of R2017a's memoize()
Note: you should test that the results are the same as the previous... they should be, but I did not test that.
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