- Ensure that the function to be plot matches with the one intended.
- Adjust the radial limits "ax.RLim" as needed to ensure that the plot is displayed correctly.
- Further customizations are possible using properties of "polarplot" and "axes" objects.
polar plot
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Hi everyone! I want to plot a function like that:
the plot is in fig. 138 (c) and its expression in Ms.
What's the code?
because, I think, there is a scale factor, I use this code:
ts=linspace(0,2*pi,500);
Ms = 1-ts.*sin(ts)-0.5*cos(ts);
polar(ts,Ms)
but this generates a wrong plot. How can I do this?
Thanks a lot for your answer! Pinco
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Respuestas (1)
Sanchari
el 25 de Jul. de 2024
Hello Pinco,
The link provided does not work. However, to create a polar plot of the equation provided: [ M_s = 1 - t \sin(t) - 0.5 \cos(t) ], the following code can be used:
% Define the range for the variable t
ts = linspace(0, 2*pi, 500);
% Compute the values of Ms using the given equation
Ms = 1 - ts .* sin(ts) - 0.5 * cos(ts);
% Create the polar plot
figure;
polarplot(ts, Ms);
% Add title and labels
title('Polar Plot of M_s = 1 - t \cdot sin(t) - 0.5 \cdot cos(t)');
Output:
There can be additional customizations like adding grid lines, setting axis limits, or changing the line style and colour. Here's an example with these additional customizations:
% Define the range for the variable t
ts = linspace(0, 2*pi, 500);
% Compute the values of Ms using the given equation
Ms = 1 - ts .* sin(ts) - 0.5 * cos(ts);
% Create the polar plot
figure;
polarplot(ts, Ms, 'r', 'LineWidth', 1.5); % Red color and thicker line
% Add title and labels
title('Polar Plot of M_s = 1 - t \cdot sin(t) - 0.5 \cdot cos(t)');
% Customize the polar plot
ax = gca;
ax.ThetaGrid = 'on'; % Turn on theta grid
ax.RGrid = 'on'; % Turn on radial grid
ax.ThetaTick = 0:45:360; % Set theta tick marks every 45 degrees
ax.RLim = [-2 2]; % Set radial limits (adjust as needed)
Output:
Notes:
Hope this helps!
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