how to create a matrix from a loop using other matrix

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Adhish Aggarwal el 11 de Jul. de 2017
Respondida: Andrei Bobrov el 12 de Jul. de 2017
c = [1
2
3
4
5
6
7
8
9
10];
d = [1
0
0
-1
0
0
1
0
1
1];
i = zeros(numel(d),1);
for i1 = 2:numel(i)
if d(i1) == 1
i(i1) = c(i1);
elseif d(i1) == -1
i(i1) = c(i1)*-1;
else
i(i1) = i(i1-1);
end
end
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Rik el 11 de Jul. de 2017
So, what is your question? I only see some unformated code.
dpb el 12 de Jul. de 2017
How to vectorize I presume is the ?
? to OP, though...your loop will only set the value to succeeding for those after the first as it is sequential and passes by the first element. Is this intended or is it intended that all elements in i end up nonzero in the end?
Also, while I don't have an issue with using i as a loop index or temporary in defiance of the builtin definition, I would recommend to NOT use it as a result variable array as here. Pick another variable name for the real case.

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Andrei Bobrov el 12 de Jul. de 2017
out = d.*c;
t = d ~= 0;
cc = out(t);
out = cc(cumsum(t));
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