Info
La pregunta está cerrada. Vuélvala a abrir para editarla o responderla.
What's wrong with the code?
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
The code supposed to delete an element from B cell if corresponding P = 0. Please help me to fix it. Thanks, George.
L = [1 10 15];
L_cell = num2cell(L);
P_max = [100;150;200];
Pg = [90 150 150];
B = [1;2;3];
for k = 1:length(L)
P_d{k} = P_max*L_cell{k};
P{k}=P_d{k} - Pg';
B_cell{k} = num2cell(B);
if (P{k}(:) == 0)
B_cell{k}(:) = [];
end
end
0 comentarios
Respuestas (1)
Adam
el 8 de Ag. de 2017
Editada: Adam
el 8 de Ag. de 2017
Simple use of the debugger or even just the command line would help you solve this.
>> P{k}(:)
ans =
1410
2100
2850
This cannot be tested by equality against 0 in an if statement (or rather not in the way you would want it to be).
It isn't obvious what you want in this case, but
doc all
doc any
will solve the problem in 2 different ways depending on what logic you want, e.g.
if ( all( P{k}(:) == 0 ) )
or
if ( any( P{k}(:) == 0 ) )
2 comentarios
Adam
el 8 de Ag. de 2017
The point is though that P{k} contains 3 elements, not just one. So P == 0 does not make sense in this context.
La pregunta está cerrada.
Ver también
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!