The complex number integration

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lick liao
lick liao el 13 de Sept. de 2017
Comentada: Star Strider el 14 de Sept. de 2017
I have some complex number integration to solve.
Here is my equation: z=exp^(j*2*pi*f) H=(abs(2*z^(-1)-z^(-2)))^2
I want to calculate the integtion of H from f=0 to f=a
I use the int(), but it only return the function I write. It seems it can't calculate out the answer.
Is someone who know how to deal with the problem? Thank for your reply!

Respuesta aceptada

Star Strider
Star Strider el 13 de Sept. de 2017
I would eliminate the abs call until the end, using it on the integrated function only after you evaluate it numerically.
Try this:
syms a f real
z(f) = exp(1j*2*pi*f);
H(f) = (2/z - 1/z^2)^2;
H = rewrite(H, 'sincos'); % Optional, If You Want a Trigonometric Result
IH = int(H, f, 0, a);
IH = simplify(IH, 'Steps', 20)
  2 comentarios
lick liao
lick liao el 14 de Sept. de 2017
Editada: lick liao el 14 de Sept. de 2017
Thanks a lot.
You give me another way to think about the equation.
I transfer H(z) to trigonometric form, then get the final answer.
Star Strider
Star Strider el 14 de Sept. de 2017
As always, my pleasure.

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