I have 3D matrix A=50x60x180 and I want subtract B=50x60 to get same size C=50x50x180? Can anybody use for loop to do this operation?

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John Chilleri
John Chilleri el 21 de Sept. de 2017
C = zeros(50,60,180);
for i = 1:180
C(:,:,i) = A(:,:,i) - B;
end
Is this what you mean?
Andrei Bobrov
Andrei Bobrov el 21 de Sept. de 2017
?
size of the C -> [50x 50 x180]? Maybe - [50x 60 x180]

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 Respuesta aceptada

Andrei Bobrov
Andrei Bobrov el 21 de Sept. de 2017

1 voto

C = A - B;
or
C = bsxfun(@minus,A,B);

2 comentarios

Walter Roberson
Walter Roberson el 21 de Sept. de 2017
The first of those works in R2016b or later but not in earlier versions.
Andrei Bobrov
Andrei Bobrov el 21 de Sept. de 2017
Walter! I am agree with you!

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