How can i make comparison faster
4 visualizaciones (últimos 30 días)
Mostrar comentarios más antiguos
Mats
el 26 de Oct. de 2017
Comentada: Andrei Bobrov
el 26 de Oct. de 2017
My aim with the loop is to pick out all elements of C that are within range r of rd and range t of td (rd and td are range matrices). Then multiply the elements together and add them to a sum.
This loop is called about a million times and is relatively slow.
Does anyone have an idea of how I can increase the speed of the loop? (I have tried code generation which turned out slower, and parallelism)
for i = 1:indN
D = C(rd(ind(i),:)<r & td(ind(i),:)<t); % Check for <r and <t
if (isempty(D)) D=0; end
gSum = gSum + prod(D);
end
Profiling gives that D=C(.. line takes 84,7% of the entire run time (the other lines in the loop next to nothing)
1 comentario
Jan
el 26 de Oct. de 2017
Please provide some test data. Optimizing code depends on the inputs also. E.g. it matters, if there are repetitions in ind, or if C is a [1e7 x 1e2] or [1e2 x 1e7] matrix.
Respuesta aceptada
Jan
el 26 de Oct. de 2017
index = (rd(ind, :) >= r | td(ind, :) >= t);
D = C;
D(index) = 1;
gSum = sum(prod(D, 2));
1 comentario
Andrei Bobrov
el 26 de Oct. de 2017
+1! Nice!
Small fixed:
D = ones(numel(ind),1)*C(:)';
Más respuestas (1)
Andrei Bobrov
el 26 de Oct. de 2017
Editada: Andrei Bobrov
el 26 de Oct. de 2017
[ii,jj] = find(rd(ind,:) < r & td(ind,:) < t);
gSum = sum(accumarray(ii,C(jj),[],@(x)prod(x)));
0 comentarios
Ver también
Categorías
Más información sobre Loops and Conditional Statements en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!