Extreact Information from a String
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Christian Berwanger
el 2 de Nov. de 2017
Comentada: Jos (10584)
el 5 de Ag. de 2019
Hello, I do have the following Code
d = dir('/home/user/Documents/Data*.inp');
names = {d.name}
which gives me an Array of Strings.
names(1) is like = "Data_c11_t3.322111_id01111_Units.inp"
names(2) is like = "Data_c101_t4.32111_id01112_Units.inp"
etc.
Now I want to extract the time, which is in the name after "t". How can I extract the time in such a format?
Any suggestions?
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Respuesta aceptada
KL
el 2 de Nov. de 2017
Editada: KL
el 2 de Nov. de 2017
regexp would be the best idea, I've no big experiences with it, I'll give it a shot anyway,
names = {'Data_c11_t3.322111_id01111_Units.inp';'Data_c101_t4.32111_id01112_Units.inp'};
t = regexp(names,'[0-9]+\.+[0-9*]+','match')
4 comentarios
Guillaume
el 3 de Nov. de 2017
To each their own opinion of course. Regular expressions are designed to extract specific patterns in strings, which, in my opinion is exactly the problem at hand.
Más respuestas (2)
Jos (10584)
el 3 de Nov. de 2017
Use a sscanf to read the number between the _t and _id, ignoring the varying number after the _c. Use cellfun to apply this to all cells:
names = {'Data_c11_t3.322111_id01111_Units.inp' ; 'Data_c101_t4.32111_id01112_Units.inp'} ;
T = cellfun(@(N) sscanf(N,'Data_c%*d_t%f_id'), names) % "%*d" = the * means skip
3 comentarios
Coco Newton
el 2 de Ag. de 2019
@Jos, this is a great answer
How would I adapt the sscanf formatSpec to extract 130 as a numeric value from this string? I have attached the string array variable that this is example string is taken from.
'Position: (19.59862|1.8|53.84677)Rotation: (0 | 130 | 0)'
Many thanks!
Jos (10584)
el 5 de Ag. de 2019
Thanks :-) Something along these lines should work for your input
str = 'Position: (19.59862|1.8|53.84677)Rotation: (0 | 130 | 0)'
A = sscanf(str, 'Position: (%*f|%*f|%*f)Rotation: (%*d | %d | %*d)')
KSSV
el 2 de Nov. de 2017
Editada: KSSV
el 2 de Nov. de 2017
str = 'Data_c11_t3.322111_id01111_Units.inp' ;
idx = strfind(str,'_') ;
str2num(str(idx(2)+2:idx(3)-1))
Using regexp:
str = 'Data_c11_t3.322111_id01111_Units.inp' ;
N = str2num( regexprep( str, {'\D*([\d\.]+\d)[^\d]*', '[^\d\.]*'}, {'$1 ', ' '} ) ) ;
t = N(2)
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