For loop in a for loop doesn't work

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Nicola Caldognetto
Nicola Caldognetto el 4 de Nov. de 2017
Respondida: Nicola Caldognetto el 5 de Nov. de 2017
So I'm playing with audio data and I have created a script which downsamples an audio file. Now I'm trying to write a script that tries to recompose the original audio copying the value of the data lost with the downsampling. This is my script
prompt = 'Specific matrix ';
matrix = input(prompt); %audio matrix 1 column
prompt = 'Specific frequency destination ';
freqdest = input(prompt);
prompt = 'Specific frequency signal ';
frq = input(prompt);
sstep = freqdest/frq;
X=ones(length(matrix)*sstep,1); %creating the new matrix
for n=1:length(matrix) % n counter matrix total
for m=0:sstep-1
X(n+m)=matrix(n);
end
end
The inside for
for m=0:sstep-1
X(n+m)=matrix(n);
end
Seems not working at all. The script creates correctly the matrix with the right dimension but copy all the value of "matrix" in "X" without launch the script for every value. Why? Has someone a solution? Thanks

Respuesta aceptada

Nicola Caldognetto
Nicola Caldognetto el 5 de Nov. de 2017
for n=1:length(matrix) % n counter matrix total
for m=0:sstep-1
X(n+m+h)=matrix(n);
end
h=h+sstep-1;
end
This is the right loop

Más respuestas (3)

M
M el 4 de Nov. de 2017
You should be careful when manipulating matix.
M(i,j)
returns the value of the ith row and jth column of the matrix.
In your example you just give one argument to your matrices.
  2 comentarios
Nicola Caldognetto
Nicola Caldognetto el 4 de Nov. de 2017
Yeah because my matrix has only one column. I have tried also with ,1 but it doesn't work
Walter Roberson
Walter Roberson el 4 de Nov. de 2017
That is okay. The comments indicate that it is a vector with one column.

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Walter Roberson
Walter Roberson el 4 de Nov. de 2017
X(n+m)=matrix(m);
perhaps? You were always copying the same value, matrix(n)
  1 comentario
Nicola Caldognetto
Nicola Caldognetto el 5 de Nov. de 2017
yeah because the internal loop copy the same value for sstep times but when it ends it should go through the next n values, but it doesn't

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Jan
Jan el 5 de Nov. de 2017
Use the debugger to find out, what's going on: Set a breakpoint inside the loop and step through the code line by line observing the values of the counters.
for n=1:length(matrix) % n counter matrix total
for m=0:sstep-1
X(n+m)=matrix(n);
end
end
Note that e.g. x(2) is assigned by n=1 and m=1 and by n=2 and m=2. Perhaps you want:
X = repmat(matrix, 1, sstep)
or
X = repelem(matrix, 1, sstep)
or perhaps the same with matrix(:) or a transposition.
  1 comentario
Nicola Caldognetto
Nicola Caldognetto el 5 de Nov. de 2017
Oh I found the bug thanks to your phrase "n=1 and m=1 and by n=2 and m=2" It's my logic error, I will fix it and post the correct code

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