Matching based on the first word
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
Danielle Leblance
el 10 de Nov. de 2017
Hi,
I have two cell arrays A and B where each contains companies names: for example A contains "Biotech Capital Corp" while B contains the same company but listed differently "BIOTECH CAP CORP". Can I match A and B based on the first word in the text? I mean can i write a code that tells that "Biotech Capital Corp" matches "BIOTECH CAP CORP" based on teh first word in the two strings "biotech" ?
0 comentarios
Respuesta aceptada
Jan
el 10 de Nov. de 2017
Editada: Jan
el 10 de Nov. de 2017
A_list = {'Biotech Capital Corp', 'Apple something', 'tesla something else'};
B_list = {'Volvo Car AB', 'BIOTECH CAP CORP', 'TESLA by Elon Musk'};
A1 = strtok(A_list, ' ');
B1 = strtok(B_list, ' ');
[LiA, LocB] = ismember(lower(A1), lower(B1)); % Or the other way around
[AInd, BInd] = CStrAinBP(strtok(A_list), strtok(B_list), 'i')
0 comentarios
Más respuestas (2)
per isakson
el 10 de Nov. de 2017
Editada: per isakson
el 10 de Nov. de 2017
Yes, try this
match = cssm()
match =
0 1 0
0 0 0
0 0 1
A_list items on the rows and B_list on the columns, i.e.
- the first item in A_list matches the second item in B_list.
- the fourth item in A_list matches the fourth item in B_list.
where
function match = cssm()
A_list = {'Biotech Capital Corp', 'Apple something', 'tesla something else'};
B_list = {'Volvo Car AB', 'BIOTECH CAP CORP', 'TESLA by Elon Musk'};
match = false( length( A_list ), length( B_list ) );
for jj = 1 : length( A_list )
a1 = regexp( A_list{jj}, '\<\w+\>', 'once', 'match' );
xpr = sprintf( '\\<%s\\>', a1 );
cac = regexpi( B_list, xpr );
%
match( jj, : ) = cellfun( @(pos) not(isempty(pos))&&pos==1, cac );
end
end
0 comentarios
KSSV
el 10 de Nov. de 2017
Read about strcmpi. It compares strings irrespective of what case they are in.
Ver también
Categorías
Más información sobre Genomics and Next Generation Sequencing en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!