How could i know if there's still NaN in a matrix?

For example, i have a matrix like this: A:

     2     1     4     5     2
     3     4     5     6     2
     5     3   NaN     3   NaN
     4     2     1     9     3
     7     1     8     2     4

My pseudocode is like this:

while there's still NaN in a matrix A

%i will do the process here to fill the Nan

then, this process will stop until there's no NaN in matrix A again.

What to do? Thanks before :')

Answer 1

[Walter Roberson]

hasnan = any(isnan(A(:)));
while hasnan
  %fill a nan at this point
  hasnan = any(isnan(A(:)));
end

In your earlier version of this question (which you deleted after I responded :( ) you were filling the NaN with a constant value, 10 in your example. If all of the NaN are to be filled with the same value, then the code can be simplified to

A(isnan(A)) = TheConstantValue;

[Isti]

i'm sorry before. because there's something error in my internet connection before :( actually i'm really thankful for your answer :)

for your previous answer: A(isnan(A)) = TheConstantValue;

it doesn't suitable for my process.

then, i'll try your solution above. anyway, i still thanks :)

[Isti]

it comes into looping forever when i try it :(

[Walter Roberson]

If it is looping forever then you have not filled in at least one nan at the place I put the comment; my comment corresponds to your pseudocode "%i will do the process here to fill the Nan".

[Isti]

ok. thank you. i can get it now :)