i have S 300x800 data set matrix , i need code for replacing coloumns
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ihab
el 31 de Dic. de 2017
Comentada: Star Strider
el 31 de Dic. de 2017
i have S 300x800 data set matrix , i need code for replacing column 120 with 50,and 120 with 121,and 240 with 100 and 240 with 241 ,and 360 with 150 and 360 with 361,.. what is the easy way of doing it with large data set 50 matrix of 300x800 each ?
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Walter Roberson
el 31 de Dic. de 2017
I notice that you have listed two replacement columns for each column. Are you looking to replace one column each time?
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Star Strider
el 31 de Dic. de 2017
I cannot claim that this is completely robust since I’ve experimented only with this code. I appears to do the same operation in one line, without the loops:
M = bsxfun(@times, ones(5,7), (1:7)) % Create Matrix
M(:,[2 5 7]) = M(:, [7 2 5]) % Switch Col#7 With Col#2, Col#2 With Col#5, Col#5 With Col#7
M =
1 2 3 4 5 6 7
1 2 3 4 5 6 7
1 2 3 4 5 6 7
1 2 3 4 5 6 7
1 2 3 4 5 6 7
M =
1 7 3 4 2 6 5
1 7 3 4 2 6 5
1 7 3 4 2 6 5
1 7 3 4 2 6 5
1 7 3 4 2 6 5
Experiment with it to see if it does what you want with your matrix.
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Walter Roberson
el 31 de Dic. de 2017
to_replace = 120:120:800;
for K = 1 : length(to_replace)
temp = OriginalMatrix;
temp(:,to_replace(K)) = temp(:,K*50);
NewMatrix{2*K-1} = temp;
temp = OriginalMatrix;
temp(:,to_replace(K)) = temp(:,to_replace(K)+1);
NewMatrix{2*K} = temp;
end
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