How to solve the 'Index exceeds number of subplots' error?

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Emrys
Emrys el 23 de En. de 2018
Comentada: the cyclist el 14 de Sept. de 2020
Hi guys, I have to solve this problem: I have this code:
for p=1:22
subplot(5,2,p)
end
It gives me the following error 'Index exceeds number of subplots', how can I solve it?
  2 comentarios
Iqra Jabeen
Iqra Jabeen el 13 de Sept. de 2020
how to solve 2*5 grid subplot
the cyclist
the cyclist el 14 de Sept. de 2020
Please add more detail to this question. Or, better yet, ask a brand-new question the fully explains what you want to know.

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Jan
Jan el 23 de En. de 2018
Editada: Jan el 23 de En. de 2018
If you ask subplot to draw an 11th subplot on a 5 x 2 grid, you cannot expect that it is such smart to create a new figure and reset the index to 1. Matlab cannot simply do what you mean. But you can write a corresponding command.
for p = 1:22
pp = mod(p - 1, 10) + 1;
if pp == 1
FigH = figure;
end
subplot(5, 2, pp, 'Parent', FigH);
...
end

Más respuestas (1)

the cyclist
the cyclist el 23 de En. de 2018
Editada: the cyclist el 23 de En. de 2018
The way you have defined the subplot layout, you have a 5-by-2 grid of subplots, which is a total of 10 subplot locations. But you are trying to place 22 subplots.
You need to increase the number of subplot locations (maybe use 5x5?), or decrease the number of subplots.
  1 comentario
Emrys
Emrys el 23 de En. de 2018
Editada: Emrys el 23 de En. de 2018
Is there any way of automatically creating new layouts? what I was expecting were three figures, 2 with 10 elements and one with 2 .

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