
Draw Triangle using quiver3 command in Matlab
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iam
el 28 de Feb. de 2018
Comentada: Star Strider
el 21 de Mzo. de 2018
Following are the position vectors that form vertices of a right angled triangle, a=[2 3 4], b=[6 2 -5], c=[8 1 -4]. I want to plot triangle using quiver3 command in Matlab. Any help will be appreciated. Thanks.
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Star Strider
el 28 de Feb. de 2018
Editada: Star Strider
el 28 de Feb. de 2018
Try this:
a=[2 3 4];
b=[6 2 -5];
c=[8 1 -4];
abc = [a; b; c; a];
dabc = diff([abc; a]);
figure(1)
plot3(abc(:,1), abc(:,2), abc(:,3), 'pg', 'MarkerSize',15, 'MArkerFaceColor','g')
hold on
quiver3(abc(:,1), abc(:,2), abc(:,3), dabc(:,1), dabc(:,2), dabc(:,3), 0, 'LineWidth',2)
hold off
grid on
xlabel('X')
ylabel('Y')
zlabel('Z')
view(150, 40)

Experiment to get the result you want. I do not know how well this will generalise to other shapes.
EDIT — Improved efficiency of the ‘dabc’ calculation.
6 comentarios
Gavin Seddon
el 21 de Mzo. de 2018
Hello Star strider how do I change the position of the arrowhead so it is at the hypotenuse terminus? Thank you. GS.
Star Strider
el 21 de Mzo. de 2018
@Gavin Seddon — I do not understand what you are asking.
I encourage you to experiment with the code to get the result you want. In the second plot (link) the points are labeled, so you can follow them more easily.
The code with the labeled vertices is:
a=[2 3 4];
b=[6 2 -5];
c=[8 1 -4];
abc = [a; b; c; a];
dabc = diff([abc; a]);
figure(1)
plot3(abc(:,1), abc(:,2), abc(:,3), 'pg', 'MarkerSize',15, 'MarkerFaceColor','g')
hold on
quiver3(abc(:,1), abc(:,2), abc(:,3), dabc(:,1), dabc(:,2), dabc(:,3), 0, 'LineWidth',2)
hold off
grid on
axis([0 10 0 5 -6 5])
text(abc(1:end-1,1), abc(1:end-1,2), abc(1:end-1,3), {'\bfa\rm','\bfb\rm','\bfc\rm'}, 'HorizontalAlignment','center', 'VerticalAlignment','bottom', 'Color','r', 'FontSize',14)
xlabel('X')
ylabel('Y')
zlabel('Z')
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