i need a nested for loop
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i need a nested for loop matlab pattern following this code :
1
121
12321
1234321
123454321
1 comentario
Jan
el 25 de Mzo. de 2018
This sounds like a homework. It would not be useful if the forum solves your homework. So please post, what you have tried so far and ask a specific question.
Respuestas (2)
Andrei Bobrov
el 22 de Mzo. de 2018
Editada: Jan
el 25 de Mzo. de 2018
ii = (1:5)';
out = arrayfun(@(ii)[1:ii,ii-1:-1:1],ii,'un',0);
or
n = 5;
A = [triu(ones(1,n).*(1:n)');flip(triu(ones(1,n).*(1:n)',1),1)];
t = A ~= 0;
B = zeros(n*2-1,n);
k = sort(t,'descend');
B(k(any(k,2),:)) = A(t);
out = B';
1 comentario
salah berra
el 25 de Mzo. de 2018
Jan
el 25 de Mzo. de 2018
A "nested for loop" is accurate enough to start:
n = 5:
for i1 = 1:n
for i2 = ???
...
end
end
Now insert, what you want to appear. fprintf('%i', v) and fprintf('\n') will help.
3 comentarios
salah berra
el 27 de Mzo. de 2018
Walter Roberson
el 27 de Mzo. de 2018
You appear to be asking that someone gives you a complete answer to a homework question.
@salah berra: I assume also, that this is a homework question. Then posting a solution is to useful, because it would be cheating, if you submit it as your solution.
All you have to do is to replace the "???" in the inner loop by some meaningful limits, to insert "fprintf('%i', v')" with replacing the "v" by one of the loop indices, and a "fprintf('\n')" as a line break. Then you have the code for:
1 12 123 1234
But now it should be easy to get the trailing part of the lines also. Example:
for i3 = 4:-1:1 disp(i3) end
I'm convinced, that you are able to do this and then submit a solution written by your own.
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