if within while loop not recognized

while(t<0.1)
if(t==0.05) v=3; end  % NOT GETTING REFLECTED IN v
t=t+Ts;
end

Answer 1

[Birdman]

A trivial answer:

Use ismembertol for comparing values with tolerance

 tol=1e-6;
 if ismembertol(t,0.05,tol)

Answer 2

[John D'Errico]

NEVER test for exact equality of a floating point number.

Since doubles are stored in binary, remember that almost all decimal fractions cannot be represented exactly as a double, just like you cannot represent 1/3 exactly as a terminating decimal in a limited number of decimal digits. Doubles use 52 binary bits to store the mantissa, so that is your limit.

Instead, 0.05 is stored as the closest value possible. So never test for exact equality. Just use a tolerance.

if abs(t - 0.05) < 1e-16