How can I fix the code?
Información
La pregunta está cerrada. Vuélvala a abrir para editarla o responderla.
Mostrar comentarios más antiguos
I'm trying to calculate the sum of f(z1^i,z2^j) for i,i=1:2m and x1,x2 are chosen before (are nodes). Here is my code in Matlab
% code
k=5;r0=0.5; M=1000; m=100; h=r0/m;
ui=@(x,y) exp(5i*y);
a=@(x,y)( 0.01*exp(1-(0.25/(0.25-x.^2-y.^2))).*(x.^2+y.^2 < 0.25)+0.*( x.^2+y.^2 >=0.25));
% a=0.01*exp(1-(0.25/(0.25-x^2-y^2) if x^2+y^2 < 0.25 and a=0 otherwise.
f=@(x1,x2,y1,y2) -1i.*k.^2./4.*besselh(0,sqrt((x1-y1).^2+(x2-y2).^2)).*a(y1,y2).*ui(y1,y2);
s=0;
for p=1:2*m
x1=-r0+p*h;
for q=1:2*m
x2=-r0+q*h;
for i=1:2*m
z1=-r0+(i/2)*h;
for j=1:2*m
z2=-r0+(j/2)*h;
s=s+f(x1,x2,z1,z2);
disp(s);
disp(f(x1,x2,z1,z2));
end
end
end
Matlab can't show the results of 's' but can show the results of 'f(x1,x2,z1,z2)'. How can I fix the code?
2 comentarios
Walter Roberson
el 30 de Jul. de 2018
What happens if you try to display s? Is there an error message?
Anh Thu
el 31 de Jul. de 2018
Respuestas (1)
OCDER
el 30 de Jul. de 2018
For some reason, you're getting a NaN + NaNi, a complex imaginary NaN. Try to skip these, otherwise s will just become NaN + NaN*i.
% code
k=5;r0=0.5; M=1000; m=100; h=r0/m;
ui=@(x,y) exp(5i*y);
a=@(x,y)( 0.01*exp(1-(0.25/(0.25-x.^2-y.^2))).*(x.^2+y.^2 < 0.25)+0.*( x.^2+y.^2 >=0.25));
% a=0.01*exp(1-(0.25/(0.25-x^2-y^2) if x^2+y^2 < 0.25 and a=0 otherwise.
f=@(x1,x2,y1,y2) -1i.*k.^2./4.*besselh(0,sqrt((x1-y1).^2+(x2-y2).^2)).*a(y1,y2).*ui(y1,y2);
s=0;
for p=1:2*m
x1=-r0+p*h;
for q=1:2*m
x2=-r0+q*h;
for i=1:2*m
z1=-r0+(i/2)*h;
for j=1:2*m
z2=-r0+(j/2)*h;
Out = f(x1,x2,z1,z2);
if ~isreal(Out); continue; end
s=s+Out;
disp(s);
disp(Out);
end
end
end
end
La pregunta está cerrada.
Productos
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!