How to generate a random number of n bits length?

23 visualizaciones (últimos 30 días)
Mohsin Shah
Mohsin Shah el 6 de Sept. de 2018
Comentada: John D'Errico el 18 de Nov. de 2020
Let's say a function takes input n as the bit length and outputs a random number. For example, for n = 4, the output range is [0 - 15] which also includes the range for n = 3 i.e. [0 - 7]. The function should generate the number in the range [8 - 15] and not in the range [0 - 15]. How to do this and how to generalize it for any n?
  3 comentarios
Mohsin Shah
Mohsin Shah el 6 de Sept. de 2018
For n = 3 then the output range is [0-7] which includes the range [0-3] which is for n = 2
KALYAN ACHARJYA
KALYAN ACHARJYA el 6 de Sept. de 2018
Editada: KALYAN ACHARJYA el 6 de Sept. de 2018
@Mohsin Check my answer, as per your requirement? If any modification required, let me know.

Iniciar sesión para comentar.

Respuesta aceptada

Guillaume
Guillaume el 6 de Sept. de 2018
For n = 4 it should generate a number in the range [8-15]
If I understand correctly, you want a 4 bit random number with the MSB always set to 1. That sounds like a strange requirement, probably not thought properly, but this is simply equivalent to generating a 3 bit random number and tacking 1 as the MSB. The generic version of that (generating a n-1 bit number + MSB of 1) is:
n = 4
number = randi([1, 2^(n-1)]) + 2^(n-1) - 1
  3 comentarios
ANz Eisenheim
ANz Eisenheim el 18 de Nov. de 2020
I want generate a random large sequence of bits and block the sequence. each block of data consisting of 4 bits. Can Anyone help?
John D'Errico
John D'Errico el 18 de Nov. de 2020
@ANz Eisenheim - please don't revive dead questions with a new question. If you have a new question, then ask it separately.
Regardless, what is the problem? Generate random bits as a vector. rand can do it. randi can do it. As long as the sequence is of a length that is a multiple of 4, you are done. So WTP?

Iniciar sesión para comentar.

Más respuestas (1)

KALYAN ACHARJYA
KALYAN ACHARJYA el 6 de Sept. de 2018
Editada: KALYAN ACHARJYA el 6 de Sept. de 2018
function bit_result=rand_bits(n)
result=randi([2^(n-1), 2^n]);
bit_result=de2bi(result,n)
end
  3 comentarios
KALYAN ACHARJYA
KALYAN ACHARJYA el 6 de Sept. de 2018
Editada: KALYAN ACHARJYA el 6 de Sept. de 2018
@Mohsin I have edited the answer, can you verify it?
Mohsin Shah
Mohsin Shah el 6 de Sept. de 2018
I appreciate your efforts but the edited function still doesn't work. Check the answer of Guillaume which worked for me.

Iniciar sesión para comentar.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by