Substitution problem in matlab
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Michael Elman
el 13 de Sept. de 2018
Comentada: madhan ravi
el 13 de Sept. de 2018
Hello, I'm new in matlab, and I'm trying to learn operations with variables,so I have encountered a little problem, that I don't quite understand, why
ER=subs(yp,{sx},{1})
ER=subs(yp,{sy},{1})
it's not a same thing, as
ER=subs(yp,{sx,sy},{1,1})
? In first case the answer is
-y*(exp(-x^2/sx^2)*exp(-y^2) - 1)
(and I don't want sx^2) and in the second case the answer is
-y*(exp(-x^2)*exp(-y^2) - 1)
(this is exactly, what i need)
This is my starting code:
syms x y z;
syms sx sy;
yp=y*(1-exp(-x^2/sx^2)*exp(-y^2/sy^2))
Does someone know what's the reason behind it?
1 comentario
madhan ravi
el 13 de Sept. de 2018
Editada: madhan ravi
el 13 de Sept. de 2018
Can you format the code by selecting the whole code and clicking the code button?
Respuesta aceptada
madhan ravi
el 13 de Sept. de 2018
Editada: madhan ravi
el 13 de Sept. de 2018
syms x y z;
syms sx sy;
yp=y*(1-exp(-x^2/sx^2)*exp(-y^2/sy^2))
ER=subs(yp,{sx},{1})
ER=subs(ER,{sy},{1})
ER1=subs(yp,{sx,sy},{1,1})
Reason: when you wanted to substitute for sy the second time you should type ER instead of up because you’re replacing the old equation again
TYPE:
ER=subs(ER,{sy},{1})
INSTEAD OF:
ER=subs(yp,{sy},{1})
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