What would happen if the time for function execution is bigger that the t.Period using timer object
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
Hello, guys! I am wondering what would happen if I use a timer object to execute a program, but the period of the timer is smaller than the time required for the program execution.
For example:
t = timer;
t.TimerFcn = @(~,thisEvent)disp([thisEvent.Type ' executed '...
datestr(thisEvent.Data.time,'dd-mmm-yyyy HH:MM:SS.FFF')]);
t.Period = 10;
t.ExecutionMode = 'fixedRate';
start(t)
and the time for the function execution takes, let's say 20 sec. Are there any methods which send us a message that the program could not be done, because it requires more time? Thank you!
0 comentarios
Respuestas (1)
Guillaume
el 17 de Oct. de 2018
It's completely documented in the timer documentation and the behaviour will depends on what you set the BusyMode property to. It can drop the missed task, queue it, or simply error.
1 comentario
Jan
el 17 de Oct. de 2018
+1. Exactly. And you can check manually what happens:
t.TimerFcn = @myTask;
t.BusyMode = 'drop'; % or 'queue' or 'error'
...
function myTask(TimerH, Event)
disp([Event.Type ' executed ' ...
datestr(Event.Data.time,'dd-mmm-yyyy HH:MM:SS.FFF')]
pause(11)
end
Ver también
Categorías
Más información sobre Construct and Work with Object Arrays en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!