How to average for certain pixles in an image?

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reyadh Albarakat
reyadh Albarakat el 29 de Oct. de 2018
Comentada: justin gat el 29 de Mayo de 2021
Dear All,
I have two images (A and B). Both of them for the same study area but each one has different resolution. Each pixel of 1st image (A) is 5km (5km x 5km) while the pixel size of 2nd image (B) is 30m x 30m. I want to calculate average of pixels of 2nd image which located in the same location of 1st image. Please take a look at the following figure.
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KALYAN ACHARJYA
KALYAN ACHARJYA el 29 de Oct. de 2018
Editada: KALYAN ACHARJYA el 29 de Oct. de 2018
What type of images? RGB /Gray/logical?
What does 5Km x 5Km mean?
reyadh Albarakat
reyadh Albarakat el 29 de Oct. de 2018
The type of images is Gray. 5 km mean 5 kilometer

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KALYAN ACHARJYA
KALYAN ACHARJYA el 29 de Oct. de 2018
Editada: KALYAN ACHARJYA el 29 de Oct. de 2018
Your question seems confusing to me. Generally, image averaging is very easy (considering gray image)
  1. If you consider the 3x3 size window,
  2. Just add the all neighboring nine pixels (including center pixel also) and divide by 9
  3. Replace the Center pixel by result value in step 2.
Rest of the condition to match the image first, then only do the average operation, you can do that easily.
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justin gat
justin gat el 29 de Mayo de 2021
sir can u please send me code for this
  1. i am considering 3x3 size window
  2. i am taking the average of the pixels conditons are
- if the pixel values in the window is greater than 255 then i am averaging the pixels expect 255 value pixels
- if the pixel values are less than 255 value pixels then i am taking 255 as my answer
example lets take in a 3x3 window i have 5 number of 255 pixel value and 4 number less than 255 values then 255 > 254 or any other pixel value so i am keeping 255 as same if 255< 254 or any other pixel values then i am averaging all the pixels except 255 pixel value
3. after this i have to replace the pixel value by resultent value
anyone can write code for this please as soon as possible

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