How to count the number of occurrences of each pair in a cell?
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Md Shahidullah Kawsar
el 30 de Oct. de 2018
Editada: Akira Agata
el 31 de Oct. de 2018
Suppose I have a cell array
C = {[1; 2; 3]; [1; 2; 3; 4]; [1; 2]};
c{:}
ans =
1
2
3
ans =
1
2
3
4
ans=
1
2
% where any digit won't repeat in the individual cell.
I need to find out the number of occurrences of each pair. Expected output:
Pair(1,2) = 3 occurences;
Pair(1,3) = 0;
Pair(1,4) = 0;
Pair(2,1) = 0;
Pair(2,3) = 2;
Pair(2,4) = 0;
Pair(3,1) = 0;
Pair(3,2) = 0;
Pair(3,4) = 1;
How can I find it?
2 comentarios
Rik
el 30 de Oct. de 2018
What code have you tried so far? It looks like there is a simple, naive approach with some loops that would solve it (not sure if there are some tricks you can pull to speed it up substantially).
Md Shahidullah Kawsar
el 31 de Oct. de 2018
Editada: Md Shahidullah Kawsar
el 31 de Oct. de 2018
Respuesta aceptada
Akira Agata
el 31 de Oct. de 2018
Editada: Akira Agata
el 31 de Oct. de 2018
I think one possible way would be like this:
c = {[1; 2; 3]; [1; 2; 3; 4]; [1; 2]};
Pair = [repelem((1:4)',4,1),repmat((1:4)',4,1)];
Count = zeros(size(allPair,1),1);
for kk = 1:numel(c)
d = [c{kk}(1:end-1),c{kk}(2:end)];
[~,lo] = ismember(d,Pair,'rows');
Count = Count + (histcounts(lo,1:size(Pair,1)+1))';
end
T = table(Pair,Count);
The output is:
>> T
T =
16×2 table
Pair Count
______ _____
1 1 0
1 2 3
1 3 0
1 4 0
2 1 0
2 2 0
2 3 2
2 4 0
3 1 0
3 2 0
3 3 0
3 4 1
4 1 0
4 2 0
4 3 0
4 4 0
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