Why does Matlab say my function is undefined?

So I have the following code

x=input('Enter the value x from the interval pi/6 to pi/2:');

while x<pi/6 || x>pi/2

disp(fprintf('Please enter an x value from the specified interval of pi/6 to pi/2 \n'))

x=input('Enter the value x from the interval pi/6 to pi/2:');

if x>pi/6 || x<pi/2

continue

end

end

n=input('Enter an integer for two, three, or four terms:');

while n~=2 || n~=3 || n~=4

disp(fprintf('You already entered that number or you entered an incorrect choice.\n'))

n=input('Enter an integer for two, three, or four terms:');

if n==2

y=func2(x);

Y=fprcall(x,n,y)

elseif n==3

y=func3(x);

Y=fprcall(x,n,y)

elseif n==4

y=func4(x);

Y=fprcall(x,n,y)

else

disp(fprintf('You already entered that number or you entered an incorrect choice.\n'))

end

end

function y=func2(x)

y=x-((x^3)/(factorial(3)));

end

function y=func3(x)

y=x-((x^3)/(factorial(3)))+((x^5)/(factorial(5)));

end

function y=func4(x)

y=x-((x^3)/(factorial(3)))+((x^5)/(factorial(5)))-((x^7)/(factorial(7)));

end

function Y=fprcall(x,n,y)

z=sin(x);

RE= (100*(y-sin(x)))/sin(x);

fprintf('For x=%0.4f and n=%f the values are y=%0.6f, sin(x)=%0.6f, and RE=%0.4f\n',x,n,y,z,RE)

end

For some reason when I run it for lets say when n=3, the function I have will not run. This occurs for all of them. Is there anything I am missing?

Answer 1

[Kelly Kearney]

If you strip out most of the commands, the main structure of your code looks like this:

n=input('Enter an integer for two, three, or four terms:');
while n~=2 || n~=3 || n~=4
    % do stuff
end

So, you ask your user to enter 2, 3, or 4... but then only execute your commands if the user starts by entering an incorrect choice.