Problems with plotting multiple objects
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Hi! I have a question. There are the label of contour on the rectangle. Can I delete this for a better reading? Thank you
This is the code for the graphic part.
[c,cc]=contour(x,y,u',[13.1,13.5,14,14.5,15,15.5,15.9]);
clabel(c,cc,'LabelSpacing',72,'Color','r','FontWeight','normal');
rectangle('position',[0,0,Lx,Ly])
rectangle('position',[x(6),y(4),d,3*d],'FaceColor',[0.5 0.5 0.5],'LineWidth',1)
axis('equal');
set(cc,'ShowText','on');
colormap cool;
axis([0 Lx 0 Ly]);
hold on;
streamline(x,y,qx,qy,[x(2:4),x(9:nx)], y(ny+1)*ones(1,6));
quiver(x(2:5),y(2:ny),qx(2:ny,2:5),qy(2:ny,2:5),'b');
quiver(x(8:nx),y(2:ny),qx(2:ny,8:nx),qy(2:ny,8:nx),'b');
quiver(x(6:7),y(2:3),qx(2:3,6:7),qy(2:3,6:7),'b');
trimesh(T,P(:,1),P(:,2),hh);
title('Sheet pile wall');
xlabel('x');ylabel('y');zlabel('z');
Respuestas (2)
MICHELA VOLGARE
el 14 de Dic. de 2018
1 comentario
Now that I understand what rectangle you mean, I removed my previous answer and added a new one. If you have any follow-up comments, reply to my answer or to the comment section under your quesiton rather than adding an 'answer' that isn't an answer.
I assume you're talking about the gray rectangle created by this line:
rectangle('position',[x(6),y(4),d,3*d],'FaceColor',[0.5 0.5 0.5],'LineWidth',1)
2 options:
Option 1. Plot the rectangle at the end of the code so it's on top of everything else.
Option 2. Save the handle to the rectangle and then after the rest of the plot is created, put the object on top of the UI stack.
rh = rectangle('position',[x(6),y(4),d,3*d],'FaceColor',[0.5 0.5 0.5],'LineWidth',1);
% the rest of your code is here..... then at the end, the next line
uistack(rh, 'top')
Note that if the rectangle is on top, it will also cover the contour lines so you may want to play around with the uistack() to position the rectangle so that you can see the contour lines but not the lables (if possible). For example, uistack(rh, 'up').
3 comentarios
MICHELA VOLGARE
el 15 de Dic. de 2018
Adam Danz
el 15 de Dic. de 2018
"Nope, nothing "
What does that mean?
MICHELA VOLGARE
el 16 de Dic. de 2018
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