Standard deviation of a 3-d matrix

hi I have a matrix with size(y)=(200*1*4). I want to calculate the std for each (200*1) vector separately. When I used "std(y(y>0)), it gave me an value but I want in fact 4 values for each 200*1 vector size. How can I write the code to give me the std for each inner vector without "for",and ....
Thanks for your help

 Respuesta aceptada

Kye Taylor
Kye Taylor el 13 de Jul. de 2012
If y is 200-by-1-by-4, you can get rid of the singleton dimension using
y2D = squeeze(y);
then compute the 4 different standard deviations using
the4Sigmas = std(y2D);

3 comentarios

Andrea
Andrea el 13 de Jul. de 2012
thanks, it was so useful. But now another question is :
I want to calculate the std for > 0. the4Sigmas = std(y2D); give me (1 by 4) value for std but when I wrote the4Sigmas = std(y2D(y2D>0)); it gave me gain a single values while I want the std to be like before (1 by 4).
Can you please help me again?
Kye Taylor
Kye Taylor el 13 de Jul. de 2012
Editada: Kye Taylor el 13 de Jul. de 2012
Sure, but next time, ask a brand new question.
I would then use a for loop
sigmasPositive = zeros(1,4);
for j = 1:size(y2D,2)
idxOfInterest = y2D(:,j) > 0;
sigmasPositive(j) = std(y2D(idxOfInterest,j));
end
or you can avoid the loop using
z = mat2cell(y2D,size(y2D,1),ones(1,size(y2D,2)));
sigmasPositiveNoLoop = cellfun(@(c)std(c(c>0)),z);
Andrea
Andrea el 13 de Jul. de 2012
Thanks a lot. I've already done that. but a little late. It works perfectly.

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