sub-gradients - reg

1 visualización (últimos 30 días)
Kallam Haranadha Reddy
Kallam Haranadha Reddy el 22 de Dic. de 2018
Respondida: Walter Roberson el 25 de Dic. de 2018
clear all
close all
clc
f1=zeros(1,100);
f2=zeros(1,100);
f3=zeros(1,200);
c1=randi([1,20],1,100);
c2=randi([1,20],1,100);
y(1,1:200)=rand(1,200);
f1(1,1:100)=[y(1,1:100).*c1];
f2(1,1:100)=[y(1,101:200).*c2];
f3(1,1:200)=horzcat(f1,f2);
g1=zeros(1,100);
g2=zeros(1,100);
g1=gradient(f1,y(1:100));
g2=gradient(f2,y(101:200));
g=horzcat(g1,g2);
my question is whether g1 and g2 are sub-gradients of f1 and f2 respectively in the above code
  4 comentarios
Kallam Haranadha Reddy
Kallam Haranadha Reddy el 25 de Dic. de 2018
sub gradient method as used in lagrangian decomposition and lagrangian relaxation algorithms

Iniciar sesión para comentar.

Respuesta aceptada

Walter Roberson
Walter Roberson el 25 de Dic. de 2018
my question is whether g1 and g2 are sub-gradients of f1 and f2 respectively in the above code
No. Lagrangian sub-gradient methods apply to functions, but you do not have functions.
gradient() applied to numeric matrices is numeric differences, and the second and following arguments give the step sizes.

Más respuestas (0)

Categorías

Más información sobre Solver Outputs and Iterative Display en Help Center y File Exchange.

Etiquetas

Productos


Versión

R2015b

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by