Borrar filtros
Borrar filtros

Integrals function computing accelerating

1 visualización (últimos 30 días)
Sara
Sara el 18 de Jul. de 2012
Hi Guys ,
- trapz
- cumtrapz
function int = Fcn_integ(x,k,dt)
x ... Signal to integration
k ... Number of integrations to be undertaken
dt ... Sampling of the signal to integration
I have implemented the above function for integration. Then I want to know it is possible to use the built-in integration function e.g., cumtrapz for this issue?Can it be helpful? Is this built-in function more optimal? By the length of x to 2500 , I have the total time around 0.642 second. Thanks in advance
  1 comentario
Jan
Jan el 18 de Jul. de 2012
How could we compare TRAPZ with your function, without knowing your function?
"More optimal" is not possible: Optimal is optimal already. "More efficient" or "faster" are more correct.

Iniciar sesión para comentar.

Respuestas (1)

Jan
Jan el 18 de Jul. de 2012
The best idea is to try it. While our suggestion will be pure speculation, because we do not know your function, you have all required data and programs to check this by your own.
  1 comentario
Sara
Sara el 19 de Jul. de 2012
I marked the two implementation (Part One and Part Two)that should give the same result , but it does not do so. The part two is correct and I want to convert it to part one with the same result. Could any one give some hints on that? It is the main part of my implementation on trapezoid method to implement integration function .
Part one :
lenx=length(x);
if k <= 0
int = x ;
return
end
int = zeros(1,length(x));
c=(k-1)/factorial(k-1);
y1 = x(2:lenx)' ;
y2 = x(1:lenx-1)' ;
tm1= dt*cumsum(tril(ones(lenx-1,lenx-1),0),1);
ans1=((tm1.^c)*y1)*dt/2;
ans2=((tm1.^c)*y2)*dt/2;
int(3:lenx) = ans1(1:lenx-2)+ ans2(2:lenx-1);
---------------------------------
Part two :
if k <= 0
int = x ;
return
end
int = zeros(1,length(x));
c=(k-1)/factorial(k-1);
dth2=dt/2;
lenx=length(x);
cmn=(lenx:-1:0)*dt;
ft1=cmn.^(c);
ft2 = (cmn+dt).^(c);
for n = 3:lenx
y1 = x(2:n) ;
t1 = ft1(lenx-n+3:lenx+1) ;
y2 = x(1:n-1) ;
t2 = ft2(lenx-n+3:lenx+1);
int(n) = sum (t1.*y1 + t2.*y2)*dth2 ;
end

Iniciar sesión para comentar.

Categorías

Más información sobre Numerical Integration and Differentiation en Help Center y File Exchange.

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by