cell array converts to matrix, how?

I want to convert cell 'A' to a matrix 'B'.
A=
columns 1 through 10
{1x1 cell} {1x1 cell} {1x1 cell} {1x1 cell}...
columns 1 through 20
{1x1 cell} {1x1 cell} {1x1 cell} {1x1 cell}...
I want to have a 'B' as:
B =
1 2 3 4 5 6 7 8 9 ... 20
I tried B(1)=cell2mat(A{1}), but can I avoid doing it one by one?
Thanks!

1 comentario

Jan
Jan el 20 de Jul. de 2012
As usual it would be helpful if you post the input data in valid Matlab syntax, such that we can try our suggestion by copy&paste them. Currently it is not clear what the "{1x1 cell}" contains. Looking at your comments it seems, like these are cell strings.

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 Respuesta aceptada

Sean de Wolski
Sean de Wolski el 19 de Jul. de 2012
B = [A{:}];
B = [B{:}];

4 comentarios

Ken
Ken el 19 de Jul. de 2012
Thanks Sean, this works for me.
:)
Ken
Ken el 19 de Jul. de 2012
Editada: Ken el 19 de Jul. de 2012
Sean, instead of getting B= 1 2 3 4 ... 20
I have B=12345678910...20. (one number)
any help?
Thanks again!
Are the contents strings?
If so, throw in a:
B = cellfun(@str2double,B);
B = [B{:}]
Ken
Ken el 19 de Jul. de 2012
Thanks!!

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Más respuestas (1)

Greg Heath
Greg Heath el 20 de Jul. de 2012

0 votos

The expressions converting a "row cell of cells" to the corresponding "row vector" are
B = [ A{ : } ]
C = [ B{ : } ]
The expression for converting a 2-D cell of cells to the corresponding 2-D matrix is
C = repmat(cell2mat( [ A{:} ] ),size(A))

5 comentarios

Jan
Jan el 20 de Jul. de 2012
I think this should be RESHAPE instead of REPMAT.
Anthony Hudetz
Anthony Hudetz el 9 de En. de 2019
Does not work for me. I tried this and get an error:
a = {1:5,2:10,3:4,4:6,5:9}
C = reshape(cell2mat( [ a{:} ] ),size(a))
Brace indexing is not supported for variables of this
type.
Error in cell2mat (line 42)
cellclass = class(c{1});
Stephen23
Stephen23 el 9 de En. de 2019
Editada: Stephen23 el 9 de En. de 2019
@Anthony Hudetz: note that Greg Heath wrote "The expression for converting a 2-D cell of cells..." Do you have a cell array of cell arrays, as Greg Heath wrote? No, you have a cell array of numeric arrays:
a = {1:5,2:10,3:4,4:6,5:9}
Perhaps this does what you want:
>> v = [a{:}]
v =
1 2 3 4 5 2 3 4 5 6 7 8 9 10 3 4 4 5 6 5 6 7 8 9
You can learn more about how this works here:
Rachel Clark
Rachel Clark el 12 de En. de 2021
is there a way to make this work for a cell array containing cell arrays of different sizes?
Dijle Kaya
Dijle Kaya el 30 de Mzo. de 2021
Editada: Dijle Kaya el 30 de Mzo. de 2021
Maybe so:
a = strings(1,length(A)) % or a = zeros(1,length(A)), if A is an integerarray
for i = 1:length(A)
a(1,i) = (convertCharsToStrings(A{i})) %if A is a Stringarray
end

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Preguntada:

Ken
el 19 de Jul. de 2012

Editada:

el 30 de Mzo. de 2021

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