I Would like to create a variable array based upon user inputs.

I have a variable that the user inputs called Type allocated as such:

n=input('How many measurements are you determining uncertainty upon?  ');

    Type=size(n)';
    Uo=1; 
          while Uo<=n;
              if Uo==1;
                  Type(Uo)=input('What type of measurement is your first measurement? (Input 1,2,or 3 for Pressure,Temperature, and Flow Rate Respectively) ');
                  Uo=Uo+1;
              elseif Uo>1;
                  Type(Uo)=input('What type of measurement is your next measurement? (Input 1,2,or 3 for Pressure,Temperature, and Flow Rate Respectively)  ');
                  Uo=Uo+1;
              end
          end 
          

I would like to use these values to create another variable matrix later in my code. I tried the following:

Factor=cell(n:1)

for iter = 1:n
    if Type == 1
        Factor{iter}=1
    elseif Type == 2
        Factor{iter}=1
    elseif Type ==3 
        Factor{iter}= 4
    elseif Type < 1 
        break
    elseif Type > 3
        break
    end
end

Could someone shine some light into what I am doing wrong here? or is there a far better method I should be using to do this?

Thanks ahead of time for any help you can lend!

[Bob Thompson]

Could someone shine some light into what I am doing wrong here?

What do you mean by wrong? Are you getting an error message? Is there some result that isn't coming out as you expect/desire?

[Adam Danz]

Also, could you provide some examples of inputs and expected outputs?

[CodeJunkie]

Sorry if I was a bit unclear basically the expected output I would like is something along the lines of if Type= [1,2,2,3,3,2,1] I would like to set a Variable factor to read type upon each iteration and return some factor. e.g. Factor=[5,6,6,8,8,6,5]. I was also hoping to make the factor possibly an equation so if I could keep it in matrix form that may be ideal rather than the cell form its currently in as one of the comments pointed out

Answer 1

[Jan]

The code contains several strange commands.

Type=size(n)'

Are you sure? Without an explanation in the comment the readers can only guess, what you want. The question "How many ..." sound like you expect a scalar input, e.g. 5. Then size(5) replies [1,1] and transposing this is [1;1].

Later you fill the elements 1 to n of Type.

Factor=cell(n:1)

Do you mean:

Factor=cell(n, 1)

n:1 is the vector from n to 1, so most likely a scalar, if n>1. Then you create a {n x n} cell matrix.

When Type is a vector, them command if Type == 3 might not do, what you expect. if requires a scalar condition, therefore an all() is inserted implicitly. I guess you mean:

if Type(iter) == 3

[CodeJunkie]

yes i meant (n,1) sorry that was a typo in the code I wrote into here. you are also correct I should specify Type per iteration it seems my issue was that simple I appreciate your help vehemently!