Root finder matlab code is not displaying result

I wrote this code below. It works without errors. However I can't see the result.
It finds the nth root of w, starting from guess g.
w=9;
g=5;
n=2;
function result=findRoot(w,g,n)
if (abs(newGuess-g)<(g*0.0001))
result = newGuess;
disp(result);
else
newGuess = (g - g^n - w) / (n*g^(n-1));
result = findRoot(w, newGuess,n);
disp(result);
end
end
I appreciate any help. Thank you.

2 comentarios

One problem is that you are calling your function from within the function:
result = findRoot(w, newGuess,n);
This will lead to ‘infinite recursion’, and so no output.
Ceyda Elcin Kaya
Ceyda Elcin Kaya el 10 de Feb. de 2019
Editada: Ceyda Elcin Kaya el 10 de Feb. de 2019
Out of memory. The likely cause is an infinite recursion within the program.
yep the exact problem I'm facing with right now. I will try to find a solution.
edit: i made it i guess. only problem left is that now it displays infinetely
w=9;
g=5;
n=2;
findRoot(w,g,n);
function [result]=findRoot(w,g,n)
newGuess=0;
while(abs(newGuess-g)>g*0.0001)
newGuess = (g - g^n - w) / (n*g^(n-1));
%result = findRoot(w, newGuess,n);
disp(newGuess)
end
result = newGuess;
disp(newGuess);
end

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Respuestas (1)

Anand Shirke
Anand Shirke el 10 de Feb. de 2019

0 votos

Maybe the problem is while declaring the function, I would suggest you to declare the function in this way
function [result]=findRoot(w,g,n)
..
.....
end
After saving the code, type in command window :
findRoot(9,5,2)

1 comentario

I did what you say. Now I'm getting a new error.
Function with duplicate name "findRoot" cannot be defined.
But my function is defined.

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Versión

R2018b

Preguntada:

el 10 de Feb. de 2019

Editada:

el 10 de Feb. de 2019

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