How can I store nested for loop values to a cell array?

I am using a nested for loop. Loop executed values are being stored in cell array but for the first row its working well but from the secong row the last cell value of first row is being repeated . how to solve this ?

[Adam]

You haven't shown any code so it's rather difficult to guess!

Answer 1

[Adam Danz]

Here's a general sketch of how to store data in a cell array within two nested for-loops. If there is something more specific you're looking for, please add some details.

myCell = cell(n,m);
for i = 1:n
    for j = 1:m
        myCell{i,j} = myFunction(data);
    end
end

[Adam Danz]

The code doesn't function without the png files and that makes it difficult to trouble shoot. But you have the png files so I can suggest where to troubleshoot.

The "profile" vector looks like it varying in length but you're never clearing that variable between iterations. In other words, imagine upon the first iteration

profile=[0 1 2 3 4 5 6]

and on the second iteration profile is supposed to equal

 profile=[9 9 9] 

but since you never cleared the variable, it actually equals

 profile=[9 9 9 3 4 5 6]

My guess is that you're storing the values in "A" correctly but you're incorrectly creating the 'profile' variable. Here's how to correct that: (assuming 'profile' is a row vector)

 profile = zeros(1, length(loo));             % <--- add this line here
 for l=1:length( loo )
      profile(l) = Y(yTop(l),xTop(l));
 end

[Zara Khan]

Thank you so much, now its working well.

But one thing I want to ask you , is there any alternative of using cell array ? Beacuse this code taking 1 hour of time to execute .

[Adam Danz]

There are alternative methods of storing values within a loop but the cell-array you've got is already a good method and it consuming microseconds of time.

When possible, you should always initialize storage variables prior to the loops. Your ell array will always have 'numImages' number of rows but since I cannot run your code, I can't easily tell how many columns it will have. If you can know ahead of time the number of columns, allocate the 'A' array prior to the loops. That will save time.

A = cell(numImages, h)

If you want to understand what part of your code is cuasing the bottleneck, you can run matlab's profile() function which will produce a table of processing times for each component of your code.

profile on
myFunction()  %<-- run your function / script
profile viewer

[Zara Khan]

Thank you .