Do an interpolation in matlab
Mostrar comentarios más antiguos
Hi,
I'm newbie in Matlab and I'm trying to do an interpolation but it doesn't work ("The values of X should be distinct.") I don't know exactly what's wrong.
load doc_1.txt
x= doc_1(:,2);
y= doc_2(:,3);
z= 399.25:1:2179.5;
yi= interp1(x,y,z);
plot(x,y,'o',z,yi)
Thanks in advance,
4 comentarios
Oleg Komarov
el 30 de Jul. de 2012
I assume "The values of X should be distinct" is an error. As it says, your x values should all be different.
klipya
el 30 de Jul. de 2012
Editada: Andrei Bobrov
el 30 de Jul. de 2012
Andrei Bobrov
el 30 de Jul. de 2012
interp1(X,Y,352,'linear','extrap')
klipya
el 6 de Ag. de 2012
Respuestas (2)
Titus Edelhofer
el 6 de Ag. de 2012
Hi,
you will need to average all values between 352 and 353. To this end use histc to find those effiently and then loop. Here ist the code (only for interval [352 - 353]), the more general should then be not too difficult:
x = [351 351.5 352.2 352.3 353.5 354.5];
y = rand(size(x));
edges = 350:355;
[n,bin] = histc(x, edges);
% for the 352 average on all values between 352 and 354
x352 = x(bin==3)
% x352 is just for illustration, what you need is y352:
y352 = mean(y(bin==3))
Titus
Andrei Bobrov
el 6 de Ag. de 2012
Editada: Andrei Bobrov
el 6 de Ag. de 2012
variant
X = [352.4, 352.5 354.3;0.5050,2.4874,1]';
[xa,~,c]=unique(fix(X(:,1)));
Xout = [xa,accumarray(c,X(:,2),[],@mean)];
Categorías
Más información sobre Interpolation en Centro de ayuda y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!