Generate random number from a two-parameter exponential distribution

Hello everybody,
I am looking for a way to easily generate random numbers from a two-parameter exponential distribution. The probability density function is: . I am aware of expand() but it does not seem to include the two-parameter distribution.
Do you have any idea how I could achieve that?
Thank you very much.
Alexis

4 comentarios

Your function f does not depend on t ?
Sorry typo :) Thank you for noticing it.
What is the support of f ?
I ask because if support(f) = IR+, f is only a probability density function if gamma = 0.

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 Respuesta aceptada

Torsten
Torsten el 21 de Mzo. de 2019
gam = ...;
lambda = ...;
n = 100;
x = gam - log(1-rand(n,1))/lambda
give you 100 random numbers distributed according to your two-parameter distribution.

1 comentario

Alexis Stevenson
Alexis Stevenson el 21 de Mzo. de 2019
Editada: Alexis Stevenson el 21 de Mzo. de 2019
Oh yes thank you so much !
I just realized the cdf was and I had to invert it.

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el 21 de Mzo. de 2019

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el 21 de Mzo. de 2019

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