Improving the speed!

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Susan
Susan el 1 de Mayo de 2019
Comentada: Susan el 1 de Mayo de 2019
Hey MATLAB guys,
Could someone please tell me how I can improve this code. It works pretty quick for nt_L=1:3. But, as nt_L increases, it takes forever. Any idea would be greatly appreciated.
K = 10;
nbrOfSubCarriers = 2*ones(1, K);
nt_L = 10;
nr_L = 3*ones(1, nt_L);
ulim_c = 1; % max value of each element
llim_c = 0; % min value of each element
sumlim_c = 1;
c0 = zeros(max(nr_L(:)), numel(nr_L), numel(nbrOfSubCarriers), max(nbrOfSubCarriers(:)));
for k = 1 : K
for m = 1 : nbrOfSubCarriers(k)
RMat = rand(max(nr_L(:)), numel(nr_L))*(ulim_c-llim_c) + llim_c;
Rsum = sum(RMat(:));
Rcheck = Rsum > sumlim_c;
while any(Rcheck)
RMat = rand(max(nr_L(:)), numel(nr_L))*(ulim_c-llim_c) + llim_c;
Rsum = sum(RMat(:));
Rcheck = Rsum > sumlim_c;
end
if Rsum <= sumlim_c
c0(:,:,k,m) = RMat;
else
c0(:,:,k,m) = RMat ./ Rsum; %makes the sum exactly 1
end
end
end

Respuesta aceptada

gonzalo Mier
gonzalo Mier el 1 de Mayo de 2019
I love this kind of problems. First of all, Matlab comes with a debugger that tell you in which part you are losing your time (It's called Run and Time). After running it, it says that the while loop is really slow, so you have to search one way to make the condition succesful in the first attemp. I have try a solution with some other modifications like the if condition which is achieve by the while.
tic
K = 10;
mult_nbrOfSubCarriers = 2;
nbrOfSubCarriers = mult_nbrOfSubCarriers*ones(1, K);
nt_L = 10;
nr_L = 3*ones(1, nt_L);
ulim_c = 1; % max value of each element
llim_c = 0; % min value of each element
sumlim_c = 1;
max_nr_L = max(nr_L(:));
numel_nr_L = numel(nr_L);
c0 = zeros(max_nr_L, numel_nr_L, K, mult_nbrOfSubCarriers);
sumlim_c2 = (sumlim_c - llim_c)/(ulim_c-llim_c);
for k = 1 : K
for m = 1 : nbrOfSubCarriers(k)
RMat = rand(max_nr_L, numel_nr_L);
sum_RMat = sum(RMat(:));
if sum_RMat > sumlim_c2
RMat = RMat./sum_RMat.*sumlim_c2;
end
c0(:,:,k,m) = RMat.*(ulim_c-llim_c) + llim_c;
end
end
toc
  1 comentario
Susan
Susan el 1 de Mayo de 2019
Thank you sooooooo much! I like the way you have improved my code. Thanks again

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