I'd like to get the index (i) for wich the condition I set in the foor loop appears on the results
Fm0= linspace(0.01,0.02,100);
%ciclo iterativo
for i=1:100
for Fm= (0.25).*(((log((2.7*10^-5)+(2.51.*((Rey.*sqrt(Fm0).^-1))))).^-1).*((log((2.7*10^-5)+(2.51.*((Rey.*sqrt(Fm0).^-1)))))).^-1)
if Fm(i)-Fm0<=10^-6
break
end
end
end

 Respuesta aceptada

Walter Roberson
Walter Roberson el 18 de Mayo de 2019

0 votos

Fm0 = linspace(0.01,0.02,100);
Fm= (0.25).*(((log((2.7*10^-5)+(2.51.*((Rey.*sqrt(Fm0).^-1))))).^-1).*((log((2.7*10^-5)+(2.51.*((Rey.*sqrt(Fm0).^-1)))))).^-1)
i = find( Fm-Fm0 <= 10^-6, 1);
You will find that the answer is 1 -- Fm0(1) > Fm(1) so the subtraction is negative and so satisfies the condition.
You might perhaps have been thinking,
i = find( abs(Fm-Fm0) <= 10^-6, 1);
but you will find that this is empty.

2 comentarios

Franco Belletti
Franco Belletti el 19 de Mayo de 2019
thanks!
Walter Roberson
Walter Roberson el 19 de Mayo de 2019
If you are looking for the value of Fm such that
Fm = (0.25).*(((log((2.7*10^-5)+(2.51.*((Rey.*sqrt(Fm).^-1))))).^-1).*((log((2.7*10^-5)+(2.51.*((Rey.*sqrt(Fm).^-1)))))).^-1)
then the value turns out to be complex, at least for positive Rey (I did not experiment with negative Rey.)

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