Problem with my if else command
1 visualización (últimos 30 días)
Mostrar comentarios más antiguos
Wei Kang Chang
el 24 de Mayo de 2019
Comentada: Luna
el 29 de Mayo de 2019
Hi all,
I have my code written as below, however it does not give me the plot that I want. Instead of using two equations according to the conditions. It gives me a graph using the else equation regardless of the value of x_15. Can anyone help me with this?
x_15=0:40:600;
if x_15<200
y_15=75*(b+500)/(a+50)*(cos(pi*x_15/200))+75*(b+500)/(a+50);
else
y_15=(exp(-x_15/150)).*(((7*(b+110)/(a+10))*(cos(pi*x_15/200)))+(7*(b+110)/(a+10)));
end
scatter(x_15,y_15);
title('S-Shaped Pipeline FEA Model');
xlabel('X position');
ylabel('Y Position');
Thank you.
Regards \
Wei Kang
0 comentarios
Respuesta aceptada
Stephen23
el 24 de Mayo de 2019
Editada: Stephen23
el 24 de Mayo de 2019
An IF statement is not appropriate (without a loop). The simple MATLAB way is to use indexing:
>> a = 1;
>> b = 1;
>> x_15 = 0:40:600;
>> idx = x_15<200; % INDEX!
>> y_15 = (exp(-x_15/150)).*(((7*(b+110)/(a+10))*(cos(pi*x_15/200)))+(7*(b+110)/(a+10)));
>> y_15(idx) = 75*(b+500)/(a+50)*(cos(pi*x_15(idx)/200))+75*(b+500)/(a+50);
% ^^^^^ ^^^^^ INDEXING!
And checking:
>> plot(x_15,y_15)
Más respuestas (0)
Ver también
Categorías
Más información sobre Matrix Indexing en Help Center y File Exchange.
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!